Quadratic Grapher — Step-by-Step Solutions
The Quadratic Grapher plots quadratic functions of the form y = ax² + bx + c and visualises the parabola, vertex, axis of symmetry, and roots. It helps you understand how the coefficients a, b, and c affect the shape and position of the graph.
Enter your coefficients to see an interactive graph with key features highlighted. Switch to vertex form or analyse the discriminant to understand the nature of the roots.
Enter coefficients for y = ax² + bx + c
Parabola Graph
Your calculations will appear here
How to Use the Quadratic Grapher
- Enter the coefficients a, b and c of y = ax^2 + bx + c. The fields start with an example (1, -2, -3); replace them with your own values, and enter 0 for a missing term.
- Graph Parabola plots the curve and lists the vertex, axis of symmetry, y-intercept, discriminant, the roots and the direction it opens.
- Vertex Form Conversion rewrites the equation as y = a(x - h)^2 + k and states whether the vertex is a minimum or a maximum.
- Discriminant Analysis shows b^2 - 4ac, whether the parabola crosses the x-axis, and the nature of the roots with the working.
Formula and Theory
The graph of y = ax^2 + bx + c is a parabola. If a is positive it opens upward and the vertex is the lowest point; if a is negative it opens downward and the vertex is the highest point. The size of a controls the width: a larger |a| makes a narrower parabola.
The vertex is at x = -b / (2a), and its y-value is found by substituting that x. The axis of symmetry is the vertical line through the vertex, x = -b / (2a). The y-intercept is the point (0, c), where the curve crosses the y-axis.
The discriminant D = b^2 - 4ac decides the roots, the points where the parabola crosses the x-axis. If D is positive there are two real roots, if D = 0 there is one repeated root and the vertex touches the axis, and if D is negative the parabola does not cross the x-axis and the roots are a pair of complex conjugates. The roots themselves come from x = (-b plus or minus sqrt(D)) / (2a).
Worked Examples
Example 1: Parabola with two real roots
Problem: Analyse y = x^2 - 4x + 3.
Solution: Vertex x = -(-4) / (2 x 1) = 2, and y = 4 - 8 + 3 = -1, so the vertex is (2, -1). D = 16 - 12 = 4 > 0. Roots: x = (4 plus or minus 2) / 2 = 3 and 1. The y-intercept is (0, 3). Vertex form: y = (x - 2)^2 - 1.
Answer: Vertex (2, -1), roots x = 1 and x = 3, y-intercept 3
Example 2: Parabola opening downward
Problem: Analyse y = -2x^2 + 4x + 1.
Solution: Vertex x = -4 / (2 x (-2)) = 1, and y = -2 + 4 + 1 = 3, so the vertex is (1, 3), a maximum because a is negative. D = 16 - 4(-2)(1) = 24. Roots: x = (-4 plus or minus 4.899) / (-4) = 2.2247 and -0.2247. Vertex form: y = -2(x - 1)^2 + 3.
Answer: Maximum at (1, 3); roots x = 2.2247 and x = -0.2247
Example 3: A repeated root
Problem: Analyse y = x^2 - 6x + 9.
Solution: D = 36 - 36 = 0, so there is one repeated root. Vertex x = 6 / 2 = 3, y = 9 - 18 + 9 = 0, so the vertex is (3, 0) and sits on the x-axis. The equation is y = (x - 3)^2.
Answer: Vertex (3, 0), repeated root x = 3
Example 4: No real roots
Problem: Analyse y = 2x^2 + 4x + 5.
Solution: D = 16 - 40 = -24 < 0, so the parabola does not cross the x-axis. Vertex x = -4 / 4 = -1, y = 2 - 4 + 5 = 3, so the vertex is (-1, 3), a minimum above the axis. Complex roots: x = -1 plus or minus (sqrt(24) / 4) i = -1 plus or minus 1.2247i.
Answer: Vertex (-1, 3); complex roots -1 plus or minus 1.2247i
Frequently Asked Questions
How do I find the vertex of a parabola?
What does the sign of a tell me?
What does the discriminant mean?
How do I find the y-intercept?
How is this different from the Quadratic Formula Calculator?
What if a is zero?
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