The Mean, Median & Mode Calculator computes the three measures of central tendency for any dataset. It finds the arithmetic mean (average), the median (middle value), and the mode (most frequent value), along with the range.
Enter your data values separated by commas and get instant results. The calculator sorts your data, shows the frequency distribution, and provides step-by-step explanations for each measure.
Your calculations will appear here
The mean (arithmetic average) is the sum of all values divided by the count. It is sensitive to extreme values (outliers). When a dataset is symmetric and has no outliers, the mean is typically the best measure of central tendency.
The median is the middle value when the data is sorted in ascending order. For an even number of values, the median is the average of the two central values. The median is more robust than the mean when outliers are present, making it the preferred measure for skewed distributions such as household income data.
The mode is the value that appears most frequently. A dataset can be unimodal (one mode), bimodal (two modes), multimodal (several modes), or have no mode at all if every value occurs with equal frequency. The mode is the only measure of central tendency that can be used with categorical (non-numeric) data.
Problem: Find the mean of: 4, 8, 6, 5, 3, 10.
Solution: Sum = 4 + 8 + 6 + 5 + 3 + 10 = 36. Count = 6. Mean = 36 / 6 = 6.
Answer: Mean = 6
Problem: Find the median of: 12, 3, 7, 9, 5.
Solution: Sort the data: 3, 5, 7, 9, 12. The middle value (position 3 out of 5) is 7.
Answer: Median = 7
Problem: Find the mode of: 2, 5, 3, 5, 7, 5, 8, 3.
Solution: Frequencies: 2 appears once, 3 appears twice, 5 appears three times, 7 appears once, 8 appears once. The most frequent value is 5.
Answer: Mode = 5
Problem: A team of 5 employees earns 30k, 32k, 35k, 37k, and 150k. Which measure best represents the "typical" salary?
Solution: Mean = (30 + 32 + 35 + 37 + 150) / 5 = 56.8k. Median = 35k (middle value). The 150k outlier inflates the mean.
Answer: The median (35k) better represents the typical salary because the mean (56.8k) is skewed by the outlier.
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